Example of Foundation of Palm Foundation

1. Foundation of the palm continuously as the picture is built on the clay soil (stiff clay) and    supports the load of 150 KN / m wall length. Thick foundation 20 cm, the weight of the concrete unit 24 KN / m3, Determine the width of the foundation, use the safety factor 3.

Clay soil with

c>0, assumptions of general shear failure

Ø=0, Nc=5,7, Nq=1, Ng=0

Review 1 m perpendicular to the image area
Capacity to support the foundation of the foundation foundation

qult= C. Nc + Po. Nq+ 0,5 g. B. Ng

qult=72,5. 5,7 + (18,8 .1,2) .1+ 0,5.18,8.B.0=

=395,21 KN/m2

the carrying capacity is safe

Load
P = Load column (wall) + foundation weight + ground load embankment =

P=150+0,2 . 24. 1 + 18,8.1,2=177,36

P netto=177,36-18,8.1,2=154,8 KN

The width is necessary
Review 1 m perpendicular to the image area

A=b. 1 so b=1,25 m

Width of foundation is used b= 1,25 m

2. The foundation structure as shown below, the square shape if the groundwater level is very deep, SF = 3, the collapse model is general shear failure. Determine the dimensions of the foundation

Settlement

Ø=30o  Nc=30, Nq=18, Ng=16

qnetto= 1,3 C. Nc + Po. (Nq -1)+ 0,4 g. B. Ng

qnetto= 1,3.20.30+1,5. 19. (18-1) + 0,4. 19. B. 16= 1264,5+121,6B

B=1,55m